Iterator exercise · helpdesk (published)

julia> Base.length(f::Fibn)=f.n

julia> collect(f(10))
10-element Vector{Any}:
  0
  1
  1
  2
  3
  5
  8
 13
 21
 34

rocco sprmnt21 (Oct 23 2021 at 17:30):

Sundar R (Oct 23 2021 at 17:30):

rocco sprmnt21 (Oct 23 2021 at 17:33):

As an alternative to using the Base prefix, could I import the functions of which I need to define a new method?
So

Sebastian Pfitzner (Oct 23 2021 at 17:51):

rocco sprmnt21 (Oct 23 2021 at 21:51):

struct Fibn{Int}
    n::Int
end
import Base: iterate, length
f(n)=Fibn(n)
length(f::Fibn)=f.n
iterate(f::Fibn) = (0,(0, 1, 1))
iterate(f::Fibn, st) = st[3] < f.n ? (st[2], (st[2], st[1]+st[2],st[3]+1)) : nothing
collect(f(17))

Mason Protter (Oct 23 2021 at 22:55):

Mason Protter (Oct 23 2021 at 23:10):

By the way the type parameter you used is a bit misleading. It defines a parameter named "Int" that can be any type

Mason Protter (Oct 23 2021 at 23:40):

julia> using Transducers; using Transducers: @next, complete

julia> struct Fibnt
           n::Int
       end

julia> function Transducers.__foldl__(rf, val, f::Fibnt)
           val = @next(rf, val, 0)
           st = (0, 1, 1)
           while st[3] < f.n
               val = @next(rf, val, st[2])
               st = (st[2], st[1]+st[2], st[3]+1)
           end
           complete(rf, val)
       end

julia> collect(Map(identity), Fibnt(17))
17-element Vector{Int64}:
   0
   1
   1
   2
   3
   5
   8
  13
  21
  34
  55
  89
 144
 233
 377
 610
 987

Mason Protter (Oct 23 2021 at 23:43):

This gives you a lot of things for free, like an efficient implementation of the sum of the sines of the first 5 Fibonacci numbers:

julia> foldl(+, Map(sin), Fibnt(5))
2.733359404501342

rocco sprmnt21 (Oct 24 2021 at 07:37):

Tanks @Mason.
In fact I don't know well the syntax of structures and types (I went a little naively, maybe too much ...)
I'll try to study your example once I understand how the iterate interface works.
For example, I don't know what's wrong with the collect (f (10)) part in the following script - the rest seems to work fine.
It seems that the iterate function that calls collect is different from the ones defined by me.
Can't I change the position of the parameters (itr and status)?
Must these parameters necessarily be two and in the above order?

struct Fib
    n::Int
end

f(n)=Fib(n)
Base.length(f::Fib)=f.n
Base.iterate(f::Fib) = ((0, 1, 1),0)
Base.iterate(st,f::Fib) = st[3] < f.n ? ((st[2], st[1]+st[2],st[3]+1),st[2]) : nothing
# this seems work

julia> f1=Base.iterate(f(10))
((0, 1, 1), 0)

julia> f2=Base.iterate(f1[1],f(10))
((1, 1, 2), 1)

julia> f3=Base.iterate(f2[1],f(10))
((1, 2, 3), 1)

#this not
julia> collect(f(5))
ERROR: MethodError: no method matching iterate(::Fib, ::Int64)

f(n)=Fib(n)

Simeon Schaub (Oct 24 2021 at 14:01):

rocco sprmnt21 (Oct 24 2021 at 16:35):

I apologize in advance if I say nonsense: I proceed a little by analogies.
I have not explicitly seen the constraint that the arguments to iterate (args ...) must be 1 or 2 and in the order itr, state.
But I am aware that thinks are like this ( (that's why I asked the questions on these aspects at the beginning of the previous message),
I wanted to understand if it was just a convention or a strict necessity.
The hand-made simulation of the iterative calls of the iterate function that I have defined seems to work.
Collect () instead seems to expect another function / method iterate.
There is a way to force the function to zero type
Base.iterate (f :: Fib) = ((0, 1, 1), 0)
so that it is of type Fib?
That is to have
Base.iterate (f :: Fib) = ((0, 1, 1), zero (Fib)).
Would this force collect () to call the iterate function with the arguments reversed?

Stream: helpdesk (published)

Topic: Iterator exercise

Sundar R (Oct 23 2021 at 17:27):