Stream: helpdesk (published)

Topic: ✔ How to vec a generator?


view this post on Zulip Júlio Hoffimann (Jul 22 2023 at 21:14):

Given the following generator:

xs = range(0, stop=1, length=10)
ys = range(0, stop=1, length=10)
((x, y) for (x, y) in Iterators.product(xs, ys))

How to "vec" it so that the result is 1-dimensional? I am currently relying on IterTools.ivec, but would like to drop this dependency.

Is there an easy workaround that doesn't rely on defining a whole new IVec struct?

view this post on Zulip Mason Protter (Jul 22 2023 at 21:21):

I’m pretty sure you can just put an if true at the end of the generator to turn it into a filtered generator and then it will lose all shape information

view this post on Zulip Jakob Nybo Nissen (Jul 22 2023 at 21:22):

Yes but it also loses its length information (making the collect significantly slower). You can call collect, then call vec on it.

view this post on Zulip Júlio Hoffimann (Jul 22 2023 at 21:35):

In my use case I actually managed to do a simpler trick:

https://github.com/JuliaGeometry/Meshes.jl/commit/16b340e5123dccbac98c742f142a987eb6b93cfd#

view this post on Zulip Júlio Hoffimann (Jul 22 2023 at 21:36):

Because I have the number of iterators a priori, I can manually add two "for" keywords to flatten the vector. This is different than a single "for" with commas.

view this post on Zulip Notification Bot (Jul 22 2023 at 21:36):

Júlio Hoffimann has marked this topic as resolved.

view this post on Zulip Júlio Hoffimann (Jul 22 2023 at 21:37):

julia> ((x, y) for (x, y) in Iterators.product(xs, ys)) |> collect
10×10 Matrix{Tuple{Float64, Float64}}:
 (0.0, 0.0)       (0.0, 0.111111)       (0.0, 0.222222)       (0.0, 0.333333)         (0.0, 0.666667)       (0.0, 0.777778)       (0.0, 0.888889)       (0.0, 1.0)
 (0.111111, 0.0)  (0.111111, 0.111111)  (0.111111, 0.222222)  (0.111111, 0.333333)     (0.111111, 0.666667)  (0.111111, 0.777778)  (0.111111, 0.888889)  (0.111111, 1.0)
 (0.222222, 0.0)  (0.222222, 0.111111)  (0.222222, 0.222222)  (0.222222, 0.333333)     (0.222222, 0.666667)  (0.222222, 0.777778)  (0.222222, 0.888889)  (0.222222, 1.0)
 (0.333333, 0.0)  (0.333333, 0.111111)  (0.333333, 0.222222)  (0.333333, 0.333333)     (0.333333, 0.666667)  (0.333333, 0.777778)  (0.333333, 0.888889)  (0.333333, 1.0)
 (0.444444, 0.0)  (0.444444, 0.111111)  (0.444444, 0.222222)  (0.444444, 0.333333)     (0.444444, 0.666667)  (0.444444, 0.777778)  (0.444444, 0.888889)  (0.444444, 1.0)
 (0.555556, 0.0)  (0.555556, 0.111111)  (0.555556, 0.222222)  (0.555556, 0.333333)    (0.555556, 0.666667)  (0.555556, 0.777778)  (0.555556, 0.888889)  (0.555556, 1.0)
 (0.666667, 0.0)  (0.666667, 0.111111)  (0.666667, 0.222222)  (0.666667, 0.333333)     (0.666667, 0.666667)  (0.666667, 0.777778)  (0.666667, 0.888889)  (0.666667, 1.0)
 (0.777778, 0.0)  (0.777778, 0.111111)  (0.777778, 0.222222)  (0.777778, 0.333333)     (0.777778, 0.666667)  (0.777778, 0.777778)  (0.777778, 0.888889)  (0.777778, 1.0)
 (0.888889, 0.0)  (0.888889, 0.111111)  (0.888889, 0.222222)  (0.888889, 0.333333)     (0.888889, 0.666667)  (0.888889, 0.777778)  (0.888889, 0.888889)  (0.888889, 1.0)
 (1.0, 0.0)       (1.0, 0.111111)       (1.0, 0.222222)       (1.0, 0.333333)          (1.0, 0.666667)       (1.0, 0.777778)       (1.0, 0.888889)       (1.0, 1.0)

julia> ((x, y) for y in ys for x in xs) |> collect
100-element Vector{Tuple{Float64, Float64}}:
 (0.0, 0.0)
 (0.1111111111111111, 0.0)
 (0.2222222222222222, 0.0)
 (0.3333333333333333, 0.0)
 (0.4444444444444444, 0.0)
 (0.5555555555555556, 0.0)
 
 (0.4444444444444444, 1.0)
 (0.5555555555555556, 1.0)
 (0.6666666666666666, 1.0)
 (0.7777777777777778, 1.0)
 (0.8888888888888888, 1.0)
 (1.0, 1.0)

view this post on Zulip Jakob Nybo Nissen (Jul 22 2023 at 22:03):

Out of curiosity does calling Vector on it work? That actually sounds like the nicest way of solving it in general

view this post on Zulip Júlio Hoffimann (Jul 22 2023 at 23:26):

You mean replacing collect with Vector @Jakob Nybo Nissen?

view this post on Zulip Júlio Hoffimann (Jul 22 2023 at 23:26):

I think we need to collect the generator before feeding it to the Vector constructor.

view this post on Zulip Jakob Nybo Nissen (Jul 23 2023 at 07:22):

Yeah... I think the Vector constructor ought to take arbitrary iterables


Last updated: Nov 06 2024 at 04:40 UTC